Base | Representation |
---|---|
bin | 1010010010100000110001… |
… | …0111000111001011111011 |
3 | 1111001112012221222001220201 |
4 | 2210220030113013023323 |
5 | 2440323313204234003 |
6 | 40021105005303031 |
7 | 2245230301631221 |
oct | 244501427071373 |
9 | 44045187861821 |
10 | 11313151243003 |
11 | 3671975a41785 |
12 | 1328693564a77 |
13 | 640a96a6a24c |
14 | 2b17b9172b11 |
15 | 1494336e2b1d |
hex | a4a0c5c72fb |
11313151243003 has 2 divisors, whose sum is σ = 11313151243004. Its totient is φ = 11313151243002.
The previous prime is 11313151242949. The next prime is 11313151243013. The reversal of 11313151243003 is 30034215131311.
It is a happy number.
11313151243003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11313151243003 - 237 = 11175712289531 is a prime.
It is not a weakly prime, because it can be changed into another prime (11313151243013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656575621501 + 5656575621502.
It is an arithmetic number, because the mean of its divisors is an integer number (5656575621502).
Almost surely, 211313151243003 is an apocalyptic number.
11313151243003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313151243003 is an equidigital number, since it uses as much as digits as its factorization.
11313151243003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 28.
Adding to 11313151243003 its reverse (30034215131311), we get a palindrome (41347366374314).
The spelling of 11313151243003 in words is "eleven trillion, three hundred thirteen billion, one hundred fifty-one million, two hundred forty-three thousand, three".
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