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113132000302 = 256566000151
BaseRepresentation
bin110100101011100110…
…0010101010000101110
3101211000100211002002021
41221113030111100232
53323143243002202
6123545551220354
711113342064446
oct1512714252056
9354010732067
10113132000302
1143a85079312
1219b138176ba
13a88c34a519
14569314b126
152e22062a37
hex1a5731542e

113132000302 has 4 divisors (see below), whose sum is σ = 169698000456. Its totient is φ = 56566000150.

The previous prime is 113132000251. The next prime is 113132000341. The reversal of 113132000302 is 203000231311.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×1131320003023 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28283000074 + ... + 28283000077.

It is an arithmetic number, because the mean of its divisors is an integer number (42424500114).

Almost surely, 2113132000302 is an apocalyptic number.

113132000302 is a deficient number, since it is larger than the sum of its proper divisors (56566000154).

113132000302 is an equidigital number, since it uses as much as digits as its factorization.

113132000302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56566000153.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 113132000302 its reverse (203000231311), we get a palindrome (316132231613).

The spelling of 113132000302 in words is "one hundred thirteen billion, one hundred thirty-two million, three hundred two", and thus it is an aban number.

Divisors: 1 2 56566000151 113132000302