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1131320011007 is a prime number
BaseRepresentation
bin10000011101100111111…
…011010110100011111111
311000011010122012011210102
4100131213323112203333
5122013420410323012
62223415442031315
7144510110266664
oct20354773264377
94004118164712
101131320011007
113a687671a90a
1216331094853b
13828b5793774
143ca82d61a6b
151e66541e2c2
hex10767ed68ff

1131320011007 has 2 divisors, whose sum is σ = 1131320011008. Its totient is φ = 1131320011006.

The previous prime is 1131320010991. The next prime is 1131320011039. The reversal of 1131320011007 is 7001100231311.

It is a weak prime.

It is an emirp because it is prime and its reverse (7001100231311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1131320011007 - 24 = 1131320010991 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1131320011007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131320011097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565660005503 + 565660005504.

It is an arithmetic number, because the mean of its divisors is an integer number (565660005504).

Almost surely, 21131320011007 is an apocalyptic number.

1131320011007 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131320011007 is an equidigital number, since it uses as much as digits as its factorization.

1131320011007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 20.

Adding to 1131320011007 its reverse (7001100231311), we get a palindrome (8132420242318).

The spelling of 1131320011007 in words is "one trillion, one hundred thirty-one billion, three hundred twenty million, eleven thousand, seven".