Base | Representation |
---|---|
bin | 110100101011100110… |
… | …0110000100011111111 |
3 | 101211000101000202110221 |
4 | 1221113030300203333 |
5 | 3323143310042002 |
6 | 123545553442211 |
7 | 11113343041456 |
oct | 1512714604377 |
9 | 354011022427 |
10 | 113132112127 |
11 | 43a85145331 |
12 | 19b13870367 |
13 | a88c3893a8 |
14 | 5693179b9d |
15 | 2e22085c37 |
hex | 1a573308ff |
113132112127 has 2 divisors, whose sum is σ = 113132112128. Its totient is φ = 113132112126.
The previous prime is 113132112097. The next prime is 113132112133. The reversal of 113132112127 is 721211231311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113132112127 - 211 = 113132110079 is a prime.
It is a super-2 number, since 2×1131321121272 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113132112727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566056063 + 56566056064.
It is an arithmetic number, because the mean of its divisors is an integer number (56566056064).
Almost surely, 2113132112127 is an apocalyptic number.
113132112127 is a deficient number, since it is larger than the sum of its proper divisors (1).
113132112127 is an equidigital number, since it uses as much as digits as its factorization.
113132112127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 504, while the sum is 25.
Adding to 113132112127 its reverse (721211231311), we get a palindrome (834343343438).
The spelling of 113132112127 in words is "one hundred thirteen billion, one hundred thirty-two million, one hundred twelve thousand, one hundred twenty-seven".
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