113132113102033 has 2 divisors, whose sum is σ = 113132113102034. Its totient is φ = 113132113102032.

The previous prime is 113132113101901. The next prime is 113132113102039. The reversal of 113132113102033 is 330201311231311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109887586321984 + 3244526780049 = 10482728^2 + 1801257^2 .

It is a cyclic number.

It is not a de Polignac number, because 113132113102033 - 2³³ = 113123523167441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113132113101989 and 113132113102007.

It is not a weakly prime, because it can be changed into another prime (113132113102039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566056551016 + 56566056551017.

It is an arithmetic number, because the mean of its divisors is an integer number (56566056551017).

Almost surely, 2^{113132113102033} is an apocalyptic number.

It is an amenable number.

113132113102033 is a deficient number, since it is larger than the sum of its proper divisors (1).

113132113102033 is an equidigital number, since it uses as much as digits as its factorization.

113132113102033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 113132113102033 its reverse (330201311231311), we get a palindrome (443333424333344).

The spelling of 113132113102033 in words is "one hundred thirteen trillion, one hundred thirty-two billion, one hundred thirteen million, one hundred two thousand, thirty-three".