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11313214303 = 421175915277
BaseRepresentation
bin10101000100101000…
…11111001101011111
31002012102210211111011
422202110133031133
5141132140324203
65110333240051
7550231510036
oct124224371537
932172724434
1011313214303
114886018396
122238933027
1310b3aa1061
1479472371d
1546330d76d
hex2a251f35f

11313214303 has 8 divisors (see below), whose sum is σ = 11347276160. Its totient is φ = 11279187360.

The previous prime is 11313214291. The next prime is 11313214343. The reversal of 11313214303 is 30341231311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11313214303 - 221 = 11311117151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313214343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 732901 + ... + 748177.

It is an arithmetic number, because the mean of its divisors is an integer number (1418409520).

Almost surely, 211313214303 is an apocalyptic number.

11313214303 is a deficient number, since it is larger than the sum of its proper divisors (34061857).

11313214303 is a wasteful number, since it uses less digits than its factorization.

11313214303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17457.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 11313214303 its reverse (30341231311), we get a palindrome (41654445614).

The spelling of 11313214303 in words is "eleven billion, three hundred thirteen million, two hundred fourteen thousand, three hundred three".

Divisors: 1 421 1759 15277 740539 6431617 26872243 11313214303