1131322010131 has 4 divisors (see below), whose sum is σ = 1131353530272. Its totient is φ = 1131290489992.

The previous prime is 1131322010107. The next prime is 1131322010153. The reversal of 1131322010131 is 1310102231311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131322010131 - 2²¹ = 1131319912979 is a prime.

It is a super-2 number, since 2×1131322010131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131322010099 and 1131322010108.

It is not an unprimeable number, because it can be changed into a prime (1131322010191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15706171 + ... + 15778036.

It is an arithmetic number, because the mean of its divisors is an integer number (282838382568).

Almost surely, 2^{1131322010131} is an apocalyptic number.

1131322010131 is a deficient number, since it is larger than the sum of its proper divisors (31520141).

1131322010131 is an equidigital number, since it uses as much as digits as its factorization.

1131322010131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31520140.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1131322010131 its reverse (1310102231311), we get a palindrome (2441424241442).

The spelling of 1131322010131 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-two million, ten thousand, one hundred thirty-one".