Base | Representation |
---|---|
bin | 10000011101101000000… |
… | …010111110101000101001 |
3 | 11000011010202221202002212 |
4 | 100131220002332220221 |
5 | 122013421413311103 |
6 | 2223415552534505 |
7 | 144510133264256 |
oct | 20355002765051 |
9 | 4004122852085 |
10 | 1131322010153 |
11 | 3a68778658a5 |
12 | 163311551435 |
13 | 828b60136aa |
14 | 3ca8332242d |
15 | 1e6656b67d8 |
hex | 107680bea29 |
1131322010153 has 2 divisors, whose sum is σ = 1131322010154. Its totient is φ = 1131322010152.
The previous prime is 1131322010107. The next prime is 1131322010191. The reversal of 1131322010153 is 3510102231311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 905841387049 + 225480623104 = 951757^2 + 474848^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131322010153 - 28 = 1131322009897 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131322010653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565661005076 + 565661005077.
It is an arithmetic number, because the mean of its divisors is an integer number (565661005077).
Almost surely, 21131322010153 is an apocalyptic number.
It is an amenable number.
1131322010153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131322010153 is an equidigital number, since it uses as much as digits as its factorization.
1131322010153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 1131322010153 its reverse (3510102231311), we get a palindrome (4641424241464).
The spelling of 1131322010153 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-two million, ten thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •