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11313220213 is a prime number
BaseRepresentation
bin10101000100101001…
…00000101001110101
31002012102211010121001
422202110200221311
5141132141021323
65110333323301
7550231533211
oct124224405165
932172733531
1011313220213
114886021879
122238936531
1310b3aa3959
14794725941
154633103ad
hex2a2520a75

11313220213 has 2 divisors, whose sum is σ = 11313220214. Its totient is φ = 11313220212.

The previous prime is 11313220069. The next prime is 11313220223. The reversal of 11313220213 is 31202231311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8581799044 + 2731421169 = 92638^2 + 52263^2 .

It is an emirp because it is prime and its reverse (31202231311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11313220213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11313220223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656610106 + 5656610107.

It is an arithmetic number, because the mean of its divisors is an integer number (5656610107).

Almost surely, 211313220213 is an apocalyptic number.

It is an amenable number.

11313220213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313220213 is an equidigital number, since it uses as much as digits as its factorization.

11313220213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11313220213 its reverse (31202231311), we get a palindrome (42515451524).

The spelling of 11313220213 in words is "eleven billion, three hundred thirteen million, two hundred twenty thousand, two hundred thirteen".