Base | Representation |
---|---|
bin | 10000011101101000000… |
… | …011011100001100010111 |
3 | 11000011010210011220011221 |
4 | 100131220003130030113 |
5 | 122013421431144343 |
6 | 2223415555311211 |
7 | 144510134310244 |
oct | 20355003341427 |
9 | 4004123156157 |
10 | 1131322131223 |
11 | 3a6877938859 |
12 | 1633115ab507 |
13 | 828b605682b |
14 | 3ca833545cb |
15 | 1e6656dc5ed |
hex | 107680dc317 |
1131322131223 has 4 divisors (see below), whose sum is σ = 1135724163120. Its totient is φ = 1126920099328.
The previous prime is 1131322131211. The next prime is 1131322131281. The reversal of 1131322131223 is 3221312231311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1131322131223 - 213 = 1131322123031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131322131283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2201015563 + ... + 2201016076.
It is an arithmetic number, because the mean of its divisors is an integer number (283931040780).
Almost surely, 21131322131223 is an apocalyptic number.
1131322131223 is a deficient number, since it is larger than the sum of its proper divisors (4402031897).
1131322131223 is an equidigital number, since it uses as much as digits as its factorization.
1131322131223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4402031896.
The product of its digits is 1296, while the sum is 25.
Adding to 1131322131223 its reverse (3221312231311), we get a palindrome (4352634362534).
The spelling of 1131322131223 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-two million, one hundred thirty-one thousand, two hundred twenty-three".
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