Base | Representation |
---|---|
bin | 1010010010100001000100… |
… | …1000101000011011110110 |
3 | 1111001112102112200001212222 |
4 | 2210220101020220123312 |
5 | 2440323444210124420 |
6 | 40021120550042342 |
7 | 2245232263451120 |
oct | 244502110503366 |
9 | 44045375601788 |
10 | 11313231333110 |
11 | 3671a07174653 |
12 | 13286b63493b2 |
13 | 640aaa52c645 |
14 | 2b17c5a60210 |
15 | 14943a763225 |
hex | a4a112286f6 |
11313231333110 has 16 divisors (see below), whose sum is σ = 23272933028256. Its totient is φ = 3878822171328.
The previous prime is 11313231333013. The next prime is 11313231333113. The reversal of 11313231333110 is 1133313231311.
It is a self number, because there is not a number n which added to its sum of digits gives 11313231333110.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313231333113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80808795167 + ... + 80808795306.
It is an arithmetic number, because the mean of its divisors is an integer number (1454558314266).
Almost surely, 211313231333110 is an apocalyptic number.
11313231333110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11313231333110 is an abundant number, since it is smaller than the sum of its proper divisors (11959701695146).
11313231333110 is a wasteful number, since it uses less digits than its factorization.
11313231333110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161617590487.
The product of its (nonzero) digits is 1458, while the sum is 26.
Adding to 11313231333110 its reverse (1133313231311), we get a palindrome (12446544564421).
The spelling of 11313231333110 in words is "eleven trillion, three hundred thirteen billion, two hundred thirty-one million, three hundred thirty-three thousand, one hundred ten".
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