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113132343233449 is a prime number
BaseRepresentation
bin11001101110010010101101…
…001000011000101110101001
3112211120100100111221220012001
4121232102231020120232221
5104312030014331432244
61040340140410051001
732554353633635461
oct3156225510305651
9484510314856161
10113132343233449
1133058180445a71
1210831980a19a61
134b184462a7547
141dd18c55c6ba1
15d12c7287b5d4
hex66e4ad218ba9

113132343233449 has 2 divisors, whose sum is σ = 113132343233450. Its totient is φ = 113132343233448.

The previous prime is 113132343233411. The next prime is 113132343233453. The reversal of 113132343233449 is 944332343231311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105236001571600 + 7896341661849 = 10258460^2 + 2810043^2 .

It is a cyclic number.

It is not a de Polignac number, because 113132343233449 - 217 = 113132343102377 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113132343233399 and 113132343233408.

It is not a weakly prime, because it can be changed into another prime (113132343233549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566171616724 + 56566171616725.

It is an arithmetic number, because the mean of its divisors is an integer number (56566171616725).

Almost surely, 2113132343233449 is an apocalyptic number.

It is an amenable number.

113132343233449 is a deficient number, since it is larger than the sum of its proper divisors (1).

113132343233449 is an equidigital number, since it uses as much as digits as its factorization.

113132343233449 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1679616, while the sum is 46.

The spelling of 113132343233449 in words is "one hundred thirteen trillion, one hundred thirty-two billion, three hundred forty-three million, two hundred thirty-three thousand, four hundred forty-nine".