Base | Representation |
---|---|
bin | 10000011101101000001… |
… | …010101000001001111101 |
3 | 11000011010220201121112221 |
4 | 100131220022220021331 |
5 | 122013422421441404 |
6 | 2223420103525341 |
7 | 144510156315052 |
oct | 20355012501175 |
9 | 4004126647487 |
10 | 1131324015229 |
11 | 3a6878a05291 |
12 | 163312159851 |
13 | 828b6566225 |
14 | 3ca836c5029 |
15 | 1e665960954 |
hex | 107682a827d |
1131324015229 has 2 divisors, whose sum is σ = 1131324015230. Its totient is φ = 1131324015228.
The previous prime is 1131324015197. The next prime is 1131324015251. The reversal of 1131324015229 is 9225104231311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1015455259204 + 115868756025 = 1007698^2 + 340395^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131324015229 - 25 = 1131324015197 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1131324015194 and 1131324015203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131324015929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565662007614 + 565662007615.
It is an arithmetic number, because the mean of its divisors is an integer number (565662007615).
Almost surely, 21131324015229 is an apocalyptic number.
It is an amenable number.
1131324015229 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131324015229 is an equidigital number, since it uses as much as digits as its factorization.
1131324015229 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 34.
The spelling of 1131324015229 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-four million, fifteen thousand, two hundred twenty-nine".
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