Base | Representation |
---|---|
bin | 10101000100101001… |
… | …00101111111111111 |
3 | 1002012102212020122002 |
4 | 22202110211333333 |
5 | 141132142221421 |
6 | 5110334012515 |
7 | 550231654103 |
oct | 124224457777 |
9 | 32172766562 |
10 | 11313242111 |
11 | 4886037276 |
12 | 223894713b |
13 | 10b3ab0902 |
14 | 79472d903 |
15 | 463316b0b |
hex | 2a2525fff |
11313242111 has 2 divisors, whose sum is σ = 11313242112. Its totient is φ = 11313242110.
The previous prime is 11313242107. The next prime is 11313242123. The reversal of 11313242111 is 11124231311.
It is a weak prime.
It is an emirp because it is prime and its reverse (11124231311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11313242111 - 22 = 11313242107 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313242141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656621055 + 5656621056.
It is an arithmetic number, because the mean of its divisors is an integer number (5656621056).
Almost surely, 211313242111 is an apocalyptic number.
11313242111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313242111 is an equidigital number, since it uses as much as digits as its factorization.
11313242111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 144, while the sum is 20.
Adding to 11313242111 its reverse (11124231311), we get a palindrome (22437473422).
The spelling of 11313242111 in words is "eleven billion, three hundred thirteen million, two hundred forty-two thousand, one hundred eleven".
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