11313243883 has 2 divisors, whose sum is σ = 11313243884. Its totient is φ = 11313243882.

The previous prime is 11313243859. The next prime is 11313243917. The reversal of 11313243883 is 38834231311.

11313243883 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (38834231311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11313243883 - 2²⁵ = 11279689451 is a prime.

It is a super-4 number, since 4×11313243883⁴ (a number of 41 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (11313243803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656621941 + 5656621942.

It is an arithmetic number, because the mean of its divisors is an integer number (5656621942).

Almost surely, 2^11313243883 is an apocalyptic number.

11313243883 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313243883 is an equidigital number, since it uses as much as digits as its factorization.

11313243883 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 37.

The spelling of 11313243883 in words is "eleven billion, three hundred thirteen million, two hundred forty-three thousand, eight hundred eighty-three".