Base | Representation |
---|---|
bin | 10101000100101001… |
… | …01000010000000010 |
3 | 1002012102212201021112 |
4 | 22202110220100002 |
5 | 141132143020310 |
6 | 5110334123322 |
7 | 550232023013 |
oct | 124224502002 |
9 | 32172781245 |
10 | 11313251330 |
11 | 4886043197 |
12 | 2238950542 |
13 | 10b3ab4b74 |
14 | 79473300a |
15 | 463319705 |
hex | 2a2528402 |
11313251330 has 32 divisors (see below), whose sum is σ = 20450707200. Its totient is φ = 4506033600.
The previous prime is 11313251309. The next prime is 11313251353. The reversal of 11313251330 is 3315231311.
It is a junction number, because it is equal to n+sod(n) for n = 11313251296 and 11313251305.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4433555 + ... + 4436105.
It is an arithmetic number, because the mean of its divisors is an integer number (639084600).
Almost surely, 211313251330 is an apocalyptic number.
11313251330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11313251330 is a deficient number, since it is larger than the sum of its proper divisors (9137455870).
11313251330 is a wasteful number, since it uses less digits than its factorization.
11313251330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4274.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 11313251330 its reverse (3315231311), we get a palindrome (14628482641).
The spelling of 11313251330 in words is "eleven billion, three hundred thirteen million, two hundred fifty-one thousand, three hundred thirty".
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