Base | Representation |
---|---|
bin | 10000011101101000100… |
… | …001011101011000100110 |
3 | 11000011011022222200200202 |
4 | 100131220201131120212 |
5 | 122013430440003142 |
6 | 2223420440110502 |
7 | 144510261223436 |
oct | 20355041353046 |
9 | 4004138880622 |
10 | 1131330000422 |
11 | 3a6881323026 |
12 | 163314165432 |
13 | 828b788056b |
14 | 3ca844022c6 |
15 | 1e666244032 |
hex | 1076885d626 |
1131330000422 has 4 divisors (see below), whose sum is σ = 1696995000636. Its totient is φ = 565665000210.
The previous prime is 1131330000413. The next prime is 1131330000467. The reversal of 1131330000422 is 2240000331311.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 1131330000394 and 1131330000403.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282832500104 + ... + 282832500107.
It is an arithmetic number, because the mean of its divisors is an integer number (424248750159).
Almost surely, 21131330000422 is an apocalyptic number.
1131330000422 is a deficient number, since it is larger than the sum of its proper divisors (565665000214).
1131330000422 is an equidigital number, since it uses as much as digits as its factorization.
1131330000422 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 565665000213.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1131330000422 its reverse (2240000331311), we get a palindrome (3371330331733).
The spelling of 1131330000422 in words is "one trillion, one hundred thirty-one billion, three hundred thirty million, four hundred twenty-two", and thus it is an aban number.
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