Base | Representation |
---|---|
bin | 11001101110010011010100… |
… | …011010001100001011100011 |
3 | 112211120102001102221110220112 |
4 | 121232103110122030023203 |
5 | 104312032342031241232 |
6 | 1040340330030201535 |
7 | 32554406155106105 |
oct | 3156232432141343 |
9 | 484512042843815 |
10 | 113133002212067 |
11 | 330584894173a2 |
12 | 10831b256532ab |
13 | 4b1851c983216 |
14 | 1dd1948d23575 |
15 | d12cb06494b2 |
hex | 66e4d468c2e3 |
113133002212067 has 2 divisors, whose sum is σ = 113133002212068. Its totient is φ = 113133002212066.
The previous prime is 113133002212033. The next prime is 113133002212127. The reversal of 113133002212067 is 760212200331311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113133002212067 - 210 = 113133002211043 is a prime.
It is not a weakly prime, because it can be changed into another prime (113133002512067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566501106033 + 56566501106034.
It is an arithmetic number, because the mean of its divisors is an integer number (56566501106034).
Almost surely, 2113133002212067 is an apocalyptic number.
113133002212067 is a deficient number, since it is larger than the sum of its proper divisors (1).
113133002212067 is an equidigital number, since it uses as much as digits as its factorization.
113133002212067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 32.
Adding to 113133002212067 its reverse (760212200331311), we get a palindrome (873345202543378).
The spelling of 113133002212067 in words is "one hundred thirteen trillion, one hundred thirty-three billion, two million, two hundred twelve thousand, sixty-seven".
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