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113133012303 = 383454349447
BaseRepresentation
bin110100101011101000…
…0001100010101001111
3101211000102201111021210
41221113100030111033
53323144022343203
6123550025025503
711113353511053
oct1512720142517
9354012644253
10113133012303
1143a856aa683
1219b14025293
13a88c61303c
145693331c63
152e221b2803
hex1a5740c54f

113133012303 has 8 divisors (see below), whose sum is σ = 152661414528. Its totient is φ = 74513309144.

The previous prime is 113133012277. The next prime is 113133012361. The reversal of 113133012303 is 303210331311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113133012303 - 25 = 113133012271 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113133012303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113133012703) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 227174475 + ... + 227174972.

It is an arithmetic number, because the mean of its divisors is an integer number (19082676816).

Almost surely, 2113133012303 is an apocalyptic number.

113133012303 is a deficient number, since it is larger than the sum of its proper divisors (39528402225).

113133012303 is an equidigital number, since it uses as much as digits as its factorization.

113133012303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 454349533.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 113133012303 its reverse (303210331311), we get a palindrome (416343343614).

The spelling of 113133012303 in words is "one hundred thirteen billion, one hundred thirty-three million, twelve thousand, three hundred three".

Divisors: 1 3 83 249 454349447 1363048341 37711004101 113133012303