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113133043995 = 357542202933
BaseRepresentation
bin110100101011101000…
…0010100000100011011
3101211000102210002202120
41221113100110010123
53323144024401440
6123550025432323
711113354002336
oct1512720240433
9354012702676
10113133043995
1143a85721474
1219b1403b6a3
13a88c6245aa
14569333d61d
152e221bbdd0
hex1a5741411b

113133043995 has 8 divisors (see below), whose sum is σ = 181012870416. Its totient is φ = 60337623456.

The previous prime is 113133043979. The next prime is 113133043999. The reversal of 113133043995 is 599340331311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 113133043995 - 24 = 113133043979 is a prime.

It is not an unprimeable number, because it can be changed into a prime (113133043999) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3771101452 + ... + 3771101481.

It is an arithmetic number, because the mean of its divisors is an integer number (22626608802).

Almost surely, 2113133043995 is an apocalyptic number.

113133043995 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

113133043995 is a deficient number, since it is larger than the sum of its proper divisors (67879826421).

113133043995 is an equidigital number, since it uses as much as digits as its factorization.

113133043995 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7542202941.

The product of its (nonzero) digits is 131220, while the sum is 42.

The spelling of 113133043995 in words is "one hundred thirteen billion, one hundred thirty-three million, forty-three thousand, nine hundred ninety-five".

Divisors: 1 3 5 15 7542202933 22626608799 37711014665 113133043995