11313310013130 has 32 divisors (see below), whose sum is σ = 27885780359424. Its totient is φ = 2935345300416.

The previous prime is 11313310013113. The next prime is 11313310013153. The reversal of 11313310013130 is 3131001331311.

It is a junction number, because it is equal to n+sod(n) for n = 11313310013097 and 11313310013106.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5096084482 + ... + 5096086701.

It is an arithmetic number, because the mean of its divisors is an integer number (871430636232).

Almost surely, 2^{11313310013130} is an apocalyptic number.

11313310013130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11313310013130 is an abundant number, since it is smaller than the sum of its proper divisors (16572470346294).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313310013130 is a wasteful number, since it uses less digits than its factorization.

11313310013130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10192171230.

The product of its (nonzero) digits is 243, while the sum is 21.

Adding to 11313310013130 its reverse (3131001331311), we get a palindrome (14444311344441).

The spelling of 11313310013130 in words is "eleven trillion, three hundred thirteen billion, three hundred ten million, thirteen thousand, one hundred thirty".