Search a number
-
+
1131331112000 = 26533135312923
BaseRepresentation
bin10000011101101000100…
…101101100110001000000
311000011011102002011111022
4100131220211230301000
5122013431231041000
62223420520005012
7144510303533255
oct20355045546100
94004142064438
101131331112000
113a6881a12191
12163314600768
13828b7b7c4bb
143ca8461142c
151e6663b3585
hex1076896cc40

1131331112000 has 224 divisors, whose sum is σ = 2900537662464. Its totient is φ = 436660224000.

The previous prime is 1131331111891. The next prime is 1131331112011. The reversal of 1131331112000 is 2111331311.

It is a self number, because there is not a number n which added to its sum of digits gives 1131331112000.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 87537539 + ... + 87550461.

Almost surely, 21131331112000 is an apocalyptic number.

1131331112000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1131331112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1450268831232).

1131331112000 is an abundant number, since it is smaller than the sum of its proper divisors (1769206550464).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131331112000 is a wasteful number, since it uses less digits than its factorization.

1131331112000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13334 (or 13314 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1131331112000 its reverse (2111331311), we get a palindrome (1133442443311).

The spelling of 1131331112000 in words is "one trillion, one hundred thirty-one billion, three hundred thirty-one million, one hundred twelve thousand".