Base | Representation |
---|---|
bin | 1010010010100001010111… |
… | …1100110001101101000110 |
3 | 1111001112122011200000220121 |
4 | 2210220111330301231012 |
5 | 2440324130400031210 |
6 | 40021132553252154 |
7 | 2245234264165330 |
oct | 244502574615506 |
9 | 44045564600817 |
10 | 11313312111430 |
11 | 3671a4882759a |
12 | 132871940405a |
13 | 640ac11a3074 |
14 | 2b17d268a450 |
15 | 1494428bc6da |
hex | a4a15f31b46 |
11313312111430 has 16 divisors (see below), whose sum is σ = 23273099200800. Its totient is φ = 3878849866752.
The previous prime is 11313312111419. The next prime is 11313312111449. The reversal of 11313312111430 is 3411121331311.
It is a junction number, because it is equal to n+sod(n) for n = 11313312111395 and 11313312111404.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80809372155 + ... + 80809372294.
It is an arithmetic number, because the mean of its divisors is an integer number (1454568700050).
Almost surely, 211313312111430 is an apocalyptic number.
11313312111430 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11313312111430 is an abundant number, since it is smaller than the sum of its proper divisors (11959787089370).
11313312111430 is a wasteful number, since it uses less digits than its factorization.
11313312111430 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 161618744463.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 11313312111430 its reverse (3411121331311), we get a palindrome (14724433442741).
The spelling of 11313312111430 in words is "eleven trillion, three hundred thirteen billion, three hundred twelve million, one hundred eleven thousand, four hundred thirty".
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