Base | Representation |
---|---|
bin | 1010010010100001011100… |
… | …0101101101110101101011 |
3 | 1111001112200111122110112211 |
4 | 2210220113011231311223 |
5 | 2440324200243411412 |
6 | 40021134515145551 |
7 | 2245234615542622 |
oct | 244502705556553 |
9 | 44045614573484 |
10 | 11313331232107 |
11 | 3671a585a7203 |
12 | 13287238a52b7 |
13 | 640ac5139188 |
14 | 2b17d50266b9 |
15 | 1494443e7ca7 |
hex | a4a1716dd6b |
11313331232107 has 2 divisors, whose sum is σ = 11313331232108. Its totient is φ = 11313331232106.
The previous prime is 11313331232009. The next prime is 11313331232123. The reversal of 11313331232107 is 70123213331311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11313331232107 is a prime.
It is not a weakly prime, because it can be changed into another prime (11313331230107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656665616053 + 5656665616054.
It is an arithmetic number, because the mean of its divisors is an integer number (5656665616054).
Almost surely, 211313331232107 is an apocalyptic number.
11313331232107 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313331232107 is an equidigital number, since it uses as much as digits as its factorization.
11313331232107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6804, while the sum is 31.
Adding to 11313331232107 its reverse (70123213331311), we get a palindrome (81436544563418).
The spelling of 11313331232107 in words is "eleven trillion, three hundred thirteen billion, three hundred thirty-one million, two hundred thirty-two thousand, one hundred seven".
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