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11313331233137 is a prime number
BaseRepresentation
bin1010010010100001011100…
…0101101110000101110001
31111001112200111122111221222
42210220113011232011301
52440324200243430022
640021134515154425
72245234615545623
oct244502705560561
944045614574858
1011313331233137
113671a585a7a5a
1213287238a5a15
13640ac513979b
142b17d5026c13
151494443e8242
hexa4a1716e171

11313331233137 has 2 divisors, whose sum is σ = 11313331233138. Its totient is φ = 11313331233136.

The previous prime is 11313331233101. The next prime is 11313331233143. The reversal of 11313331233137 is 73133213331311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10981694610496 + 331636622641 = 3313864^2 + 575879^2 .

It is a cyclic number.

It is not a de Polignac number, because 11313331233137 - 216 = 11313331167601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11313331233097 and 11313331233106.

It is not a weakly prime, because it can be changed into another prime (11313331233937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656665616568 + 5656665616569.

It is an arithmetic number, because the mean of its divisors is an integer number (5656665616569).

Almost surely, 211313331233137 is an apocalyptic number.

It is an amenable number.

11313331233137 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313331233137 is an equidigital number, since it uses as much as digits as its factorization.

11313331233137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 30618, while the sum is 35.

Adding to 11313331233137 its reverse (73133213331311), we get a palindrome (84446544564448).

The spelling of 11313331233137 in words is "eleven trillion, three hundred thirteen billion, three hundred thirty-one million, two hundred thirty-three thousand, one hundred thirty-seven".