Base | Representation |
---|---|
bin | 1010010010100001011100… |
… | …0101101110000101001101 |
3 | 1111001112200111122111220122 |
4 | 2210220113011232011031 |
5 | 2440324200243424401 |
6 | 40021134515154325 |
7 | 2245234615545542 |
oct | 244502705560515 |
9 | 44045614574818 |
10 | 11313331233101 |
11 | 3671a585a7a27 |
12 | 13287238a59a5 |
13 | 640ac5139771 |
14 | 2b17d5026bc9 |
15 | 1494443e821b |
hex | a4a1716e14d |
11313331233101 has 2 divisors, whose sum is σ = 11313331233102. Its totient is φ = 11313331233100.
The previous prime is 11313331233091. The next prime is 11313331233137. The reversal of 11313331233101 is 10133213331311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11173970877001 + 139360356100 = 3342749^2 + 373310^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11313331233101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313331233181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656665616550 + 5656665616551.
It is an arithmetic number, because the mean of its divisors is an integer number (5656665616551).
Almost surely, 211313331233101 is an apocalyptic number.
It is an amenable number.
11313331233101 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313331233101 is an equidigital number, since it uses as much as digits as its factorization.
11313331233101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 26.
Adding to 11313331233101 its reverse (10133213331311), we get a palindrome (21446544564412).
The spelling of 11313331233101 in words is "eleven trillion, three hundred thirteen billion, three hundred thirty-one million, two hundred thirty-three thousand, one hundred one".
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