113133314131 has 4 divisors (see below), whose sum is σ = 113138439064. Its totient is φ = 113128189200.

The previous prime is 113133314081. The next prime is 113133314153. The reversal of 113133314131 is 131413331311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113133314131 - 2¹⁵ = 113133281363 is a prime.

It is a super-2 number, since 2×113133314131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113133314096 and 113133314105.

It is not an unprimeable number, because it can be changed into a prime (113133314531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2529210 + ... + 2573551.

It is an arithmetic number, because the mean of its divisors is an integer number (28284609766).

Almost surely, 2^113133314131 is an apocalyptic number.

113133314131 is a deficient number, since it is larger than the sum of its proper divisors (5124933).

113133314131 is an equidigital number, since it uses as much as digits as its factorization.

113133314131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5124932.

The product of its digits is 972, while the sum is 25.

Adding to 113133314131 its reverse (131413331311), we get a palindrome (244546645442).

The spelling of 113133314131 in words is "one hundred thirteen billion, one hundred thirty-three million, three hundred fourteen thousand, one hundred thirty-one".