11313344000000 has 364 divisors, whose sum is σ = 32320760351472. Its totient is φ = 3878707200000.

The previous prime is 11313343999973. The next prime is 11313344000003. The reversal of 11313344000000 is 44331311.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (11313344000003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 447987374 + ... + 448012626.

Almost surely, 2^{11313344000000} is an apocalyptic number.

11313344000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313344000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16160380175736).

11313344000000 is an abundant number, since it is smaller than the sum of its proper divisors (21007416351472).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313344000000 is an frugal number, since it uses more digits than its factorization.

11313344000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25314 (or 25267 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 11313344000000 its reverse (44331311), we get a palindrome (11313388331311).

The spelling of 11313344000000 in words is "eleven trillion, three hundred thirteen billion, three hundred forty-four million", and thus it is an aban number.