Base | Representation |
---|---|
bin | 110100101011101010… |
… | …0011101010011101101 |
3 | 101211000111211022001021 |
4 | 1221113110131103231 |
5 | 3323144314133123 |
6 | 123550105014141 |
7 | 11113366145623 |
oct | 1512724352355 |
9 | 354014738037 |
10 | 113134130413 |
11 | 43a862a3737 |
12 | 19b14484351 |
13 | a88c914c45 |
14 | 5693543513 |
15 | 2e22333c5d |
hex | 1a5751d4ed |
113134130413 has 2 divisors, whose sum is σ = 113134130414. Its totient is φ = 113134130412.
The previous prime is 113134130327. The next prime is 113134130441. The reversal of 113134130413 is 314031431311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113096344804 + 37785609 = 336298^2 + 6147^2 .
It is a cyclic number.
It is not a de Polignac number, because 113134130413 - 229 = 112597259501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113134130113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56567065206 + 56567065207.
It is an arithmetic number, because the mean of its divisors is an integer number (56567065207).
Almost surely, 2113134130413 is an apocalyptic number.
It is an amenable number.
113134130413 is a deficient number, since it is larger than the sum of its proper divisors (1).
113134130413 is an equidigital number, since it uses as much as digits as its factorization.
113134130413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 113134130413 its reverse (314031431311), we get a palindrome (427165561724).
The spelling of 113134130413 in words is "one hundred thirteen billion, one hundred thirty-four million, one hundred thirty thousand, four hundred thirteen".
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