113134130433 has 32 divisors (see below), whose sum is σ = 177595545600. Its totient is φ = 70934024448.

The previous prime is 113134130413. The next prime is 113134130441. The reversal of 113134130433 is 334031431311.

113134130433 is a `hidden beast` number, since 1 + 1 + 313 + 41 + 304 + 3 + 3 = 666.

It is not a de Polignac number, because 113134130433 - 2⁸ = 113134130177 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 113134130397 and 113134130406.

It is not an unprimeable number, because it can be changed into a prime (113134130413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 540448 + ... + 719966.

It is an arithmetic number, because the mean of its divisors is an integer number (5549860800).

Almost surely, 2^113134130433 is an apocalyptic number.

It is an amenable number.

113134130433 is a deficient number, since it is larger than the sum of its proper divisors (64461415167).

113134130433 is a wasteful number, since it uses less digits than its factorization.

113134130433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 180918 (or 180912 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 113134130433 its reverse (334031431311), we get a palindrome (447165561744).

The spelling of 113134130433 in words is "one hundred thirteen billion, one hundred thirty-four million, one hundred thirty thousand, four hundred thirty-three".