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1131341343014 = 2565670671507
BaseRepresentation
bin10000011101101001001…
…100101110100100100110
311000011012010022221210202
4100131221030232210212
5122013441340434024
62223421523150502
7144510456514301
oct20355114564446
94004163287722
101131341343014
113a688776a973
12163317b15432
13828ba02225c
143ca85b15b38
151e667234bae
hex1076932e926

1131341343014 has 4 divisors (see below), whose sum is σ = 1697012014524. Its totient is φ = 565670671506.

The previous prime is 1131341343007. The next prime is 1131341343019. The reversal of 1131341343014 is 4103431431311.

It is a semiprime because it is the product of two primes.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131341343019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 282835335752 + ... + 282835335755.

It is an arithmetic number, because the mean of its divisors is an integer number (424253003631).

Almost surely, 21131341343014 is an apocalyptic number.

1131341343014 is a deficient number, since it is larger than the sum of its proper divisors (565670671510).

1131341343014 is an equidigital number, since it uses as much as digits as its factorization.

1131341343014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 565670671509.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1131341343014 its reverse (4103431431311), we get a palindrome (5234772774325).

The spelling of 1131341343014 in words is "one trillion, one hundred thirty-one billion, three hundred forty-one million, three hundred forty-three thousand, fourteen".

Divisors: 1 2 565670671507 1131341343014