Base | Representation |
---|---|
bin | 10101000100101010… |
… | …10100101000100100 |
3 | 1002012110012221122122 |
4 | 22202111110220210 |
5 | 141132214324444 |
6 | 5110342045112 |
7 | 550233411020 |
oct | 124225245044 |
9 | 32173187578 |
10 | 11313433124 |
11 | 4886157834 |
12 | 2238a19798 |
13 | 10b3b49836 |
14 | 79477d380 |
15 | 4633534ee |
hex | 2a2554a24 |
11313433124 has 12 divisors (see below), whose sum is σ = 22626866304. Its totient is φ = 4848614184.
The previous prime is 11313433099. The next prime is 11313433151. The reversal of 11313433124 is 42133431311.
11313433124 is an admirable number.
It is a junction number, because it is equal to n+sod(n) for n = 11313433093 and 11313433102.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202025564 + ... + 202025619.
It is an arithmetic number, because the mean of its divisors is an integer number (1885572192).
Almost surely, 211313433124 is an apocalyptic number.
11313433124 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
11313433124 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313433124 is a wasteful number, since it uses less digits than its factorization.
11313433124 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 404051194 (or 404051192 counting only the distinct ones).
The product of its digits is 2592, while the sum is 26.
Adding to 11313433124 its reverse (42133431311), we get a palindrome (53446864435).
The spelling of 11313433124 in words is "eleven billion, three hundred thirteen million, four hundred thirty-three thousand, one hundred twenty-four".
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