11313454333 has 2 divisors, whose sum is σ = 11313454334. Its totient is φ = 11313454332.

The previous prime is 11313454283. The next prime is 11313454349. The reversal of 11313454333 is 33345431311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10628166649 + 685287684 = 103093^2 + 26178^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11313454333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11313454295 and 11313454304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11313454133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656727166 + 5656727167.

It is an arithmetic number, because the mean of its divisors is an integer number (5656727167).

Almost surely, 2^11313454333 is an apocalyptic number.

It is an amenable number.

11313454333 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313454333 is an equidigital number, since it uses as much as digits as its factorization.

11313454333 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 19440, while the sum is 31.

Adding to 11313454333 its reverse (33345431311), we get a palindrome (44658885644).

The spelling of 11313454333 in words is "eleven billion, three hundred thirteen million, four hundred fifty-four thousand, three hundred thirty-three".