Base | Representation |
---|---|
bin | 10101000100101011… |
… | …10010001100111011 |
3 | 1002012110110002210020 |
4 | 22202111302030323 |
5 | 141132232213420 |
6 | 5110344421523 |
7 | 550234424064 |
oct | 124225621473 |
9 | 32173402706 |
10 | 11313554235 |
11 | 488622a825 |
12 | 2238a778a3 |
13 | 10b3b8c9b9 |
14 | 7947b156b |
15 | 463379340 |
hex | 2a257233b |
11313554235 has 32 divisors (see below), whose sum is σ = 18466812480. Its totient is φ = 5913243648.
The previous prime is 11313554207. The next prime is 11313554251. The reversal of 11313554235 is 53245531311.
11313554235 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11313554235 - 27 = 11313554107 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11313554196 and 11313554205.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 139011 + ... + 204819.
It is an arithmetic number, because the mean of its divisors is an integer number (577087890).
Almost surely, 211313554235 is an apocalyptic number.
11313554235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11313554235 is a deficient number, since it is larger than the sum of its proper divisors (7153258245).
11313554235 is a wasteful number, since it uses less digits than its factorization.
11313554235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66047.
The product of its digits is 27000, while the sum is 33.
The spelling of 11313554235 in words is "eleven billion, three hundred thirteen million, five hundred fifty-four thousand, two hundred thirty-five".
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