113140000001 has 4 divisors (see below), whose sum is σ = 129302857152. Its totient is φ = 96977142852.

The previous prime is 113139999977. The next prime is 113140000007. The reversal of 113140000001 is 100000041311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100000041311 = 19 ⋅5263160069.

It is a cyclic number.

It is not a de Polignac number, because 113140000001 - 2⁶ = 113139999937 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (113140000007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8081428565 + ... + 8081428578.

It is an arithmetic number, because the mean of its divisors is an integer number (32325714288).

Almost surely, 2^113140000001 is an apocalyptic number.

It is an amenable number.

113140000001 is a deficient number, since it is larger than the sum of its proper divisors (16162857151).

113140000001 is an equidigital number, since it uses as much as digits as its factorization.

113140000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16162857150.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 113140000001 its reverse (100000041311), we get a palindrome (213140041312).

The spelling of 113140000001 in words is "one hundred thirteen billion, one hundred forty million, one", and thus it is an aban number.