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11314003 = 35332051
BaseRepresentation
bin101011001010…
…001101010011
3210021210220011
4223022031103
510344022003
61042255351
7165111301
oct53121523
923253804
1011314003
116428418
123957557
13246199c
141707271
15ed746d
hexaca353

11314003 has 4 divisors (see below), whose sum is σ = 11346408. Its totient is φ = 11281600.

The previous prime is 11313989. The next prime is 11314007. The reversal of 11314003 is 30041311.

11314003 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11314003 is a prime.

It is a super-3 number, since 3×113140033 (a number of 22 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11314007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15673 + ... + 16378.

It is an arithmetic number, because the mean of its divisors is an integer number (2836602).

Almost surely, 211314003 is an apocalyptic number.

11314003 is a deficient number, since it is larger than the sum of its proper divisors (32405).

11314003 is an equidigital number, since it uses as much as digits as its factorization.

11314003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32404.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 11314003 is about 3363.6294385678. The cubic root of 11314003 is about 224.4943575251.

Adding to 11314003 its reverse (30041311), we get a palindrome (41355314).

The spelling of 11314003 in words is "eleven million, three hundred fourteen thousand, three".

Divisors: 1 353 32051 11314003