Base | Representation |
---|---|
bin | 110100101011110101… |
… | …1010011110010000111 |
3 | 101211000221002122012011 |
4 | 1221113223103302013 |
5 | 3323202332330321 |
6 | 123550441235051 |
7 | 11113501105222 |
oct | 1512753236207 |
9 | 354027078164 |
10 | 113140120711 |
11 | 43a897152a2 |
12 | 19b16492a87 |
13 | a890c316b7 |
14 | 56942625b9 |
15 | 2e22b18ae1 |
hex | 1a57ad3c87 |
113140120711 has 2 divisors, whose sum is σ = 113140120712. Its totient is φ = 113140120710.
The previous prime is 113140120631. The next prime is 113140120739. The reversal of 113140120711 is 117021041311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113140120711 - 29 = 113140120199 is a prime.
It is a super-2 number, since 2×1131401207112 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113140120741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56570060355 + 56570060356.
It is an arithmetic number, because the mean of its divisors is an integer number (56570060356).
Almost surely, 2113140120711 is an apocalyptic number.
113140120711 is a deficient number, since it is larger than the sum of its proper divisors (1).
113140120711 is an equidigital number, since it uses as much as digits as its factorization.
113140120711 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 22.
The spelling of 113140120711 in words is "one hundred thirteen billion, one hundred forty million, one hundred twenty thousand, seven hundred eleven".
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