11314020033 has 8 divisors (see below), whose sum is σ = 16761511200. Its totient is φ = 7542680004.

The previous prime is 11314020031. The next prime is 11314020073. The reversal of 11314020033 is 33002041311.

11314020033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11314020033 - 2¹ = 11314020031 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11314019988 and 11314020015.

It is not an unprimeable number, because it can be changed into a prime (11314020031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 209518863 + ... + 209518916.

It is an arithmetic number, because the mean of its divisors is an integer number (2095188900).

Almost surely, 2^11314020033 is an apocalyptic number.

It is an amenable number.

11314020033 is a deficient number, since it is larger than the sum of its proper divisors (5447491167).

11314020033 is an equidigital number, since it uses as much as digits as its factorization.

11314020033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 419037788 (or 419037782 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 11314020033 its reverse (33002041311), we get a palindrome (44316061344).

The spelling of 11314020033 in words is "eleven billion, three hundred fourteen million, twenty thousand, thirty-three".