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11314020203 is a prime number
BaseRepresentation
bin10101000100101111…
…00011111101101011
31002012111022202222022
422202113203331223
5141132342121303
65110402415055
7550241404433
oct124227437553
932174282868
1011314020203
114886518922
12223906148b
1310b3cc3b15
147948932c3
1546341c438
hex2a25e3f6b

11314020203 has 2 divisors, whose sum is σ = 11314020204. Its totient is φ = 11314020202.

The previous prime is 11314020199. The next prime is 11314020209. The reversal of 11314020203 is 30202041311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11314020203 - 22 = 11314020199 is a prime.

It is a super-2 number, since 2×113140202032 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11314020209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657010101 + 5657010102.

It is an arithmetic number, because the mean of its divisors is an integer number (5657010102).

Almost surely, 211314020203 is an apocalyptic number.

11314020203 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314020203 is an equidigital number, since it uses as much as digits as its factorization.

11314020203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 11314020203 its reverse (30202041311), we get a palindrome (41516061514).

The spelling of 11314020203 in words is "eleven billion, three hundred fourteen million, twenty thousand, two hundred three".