Base | Representation |
---|---|
bin | 10101000100101111… |
… | …00011111101101011 |
3 | 1002012111022202222022 |
4 | 22202113203331223 |
5 | 141132342121303 |
6 | 5110402415055 |
7 | 550241404433 |
oct | 124227437553 |
9 | 32174282868 |
10 | 11314020203 |
11 | 4886518922 |
12 | 223906148b |
13 | 10b3cc3b15 |
14 | 7948932c3 |
15 | 46341c438 |
hex | 2a25e3f6b |
11314020203 has 2 divisors, whose sum is σ = 11314020204. Its totient is φ = 11314020202.
The previous prime is 11314020199. The next prime is 11314020209. The reversal of 11314020203 is 30202041311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11314020203 - 22 = 11314020199 is a prime.
It is a super-2 number, since 2×113140202032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11314020209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657010101 + 5657010102.
It is an arithmetic number, because the mean of its divisors is an integer number (5657010102).
Almost surely, 211314020203 is an apocalyptic number.
11314020203 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314020203 is an equidigital number, since it uses as much as digits as its factorization.
11314020203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 11314020203 its reverse (30202041311), we get a palindrome (41516061514).
The spelling of 11314020203 in words is "eleven billion, three hundred fourteen million, twenty thousand, two hundred three".
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