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113140314101 is a prime number
BaseRepresentation
bin110100101011110110…
…0000010111111110101
3101211000221110110110202
41221113230002333311
53323202410022401
6123550445330245
711113502542103
oct1512754027765
9354027413422
10113140314101
1143a89837621
1219b16566985
13a890c9b729
1456942b2c73
152e22b5606b
hex1a57b02ff5

113140314101 has 2 divisors, whose sum is σ = 113140314102. Its totient is φ = 113140314100.

The previous prime is 113140314073. The next prime is 113140314167. The reversal of 113140314101 is 101413041311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66680667076 + 46459647025 = 258226^2 + 215545^2 .

It is a cyclic number.

It is not a de Polignac number, because 113140314101 - 26 = 113140314037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113140313101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56570157050 + 56570157051.

It is an arithmetic number, because the mean of its divisors is an integer number (56570157051).

Almost surely, 2113140314101 is an apocalyptic number.

It is an amenable number.

113140314101 is a deficient number, since it is larger than the sum of its proper divisors (1).

113140314101 is an equidigital number, since it uses as much as digits as its factorization.

113140314101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 113140314101 its reverse (101413041311), we get a palindrome (214553355412).

The spelling of 113140314101 in words is "one hundred thirteen billion, one hundred forty million, three hundred fourteen thousand, one hundred one".