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113140350374 = 256570175187
BaseRepresentation
bin110100101011110110…
…0001011110110100110
3101211000221112022020012
41221113230023312212
53323202412202444
6123550450210222
711113503052622
oct1512754136646
9354027468205
10113140350374
1143a898618a7
1219b16583972
13a890cb20ac
1456942c2182
152e22b61b9e
hex1a57b0bda6

113140350374 has 4 divisors (see below), whose sum is σ = 169710525564. Its totient is φ = 56570175186.

The previous prime is 113140350373. The next prime is 113140350383. The reversal of 113140350374 is 473053041311.

113140350374 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 113140350374.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113140350373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28285087592 + ... + 28285087595.

It is an arithmetic number, because the mean of its divisors is an integer number (42427631391).

Almost surely, 2113140350374 is an apocalyptic number.

113140350374 is a deficient number, since it is larger than the sum of its proper divisors (56570175190).

113140350374 is an equidigital number, since it uses as much as digits as its factorization.

113140350374 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56570175189.

The product of its (nonzero) digits is 15120, while the sum is 32.

Adding to 113140350374 its reverse (473053041311), we get a palindrome (586193391685).

The spelling of 113140350374 in words is "one hundred thirteen billion, one hundred forty million, three hundred fifty thousand, three hundred seventy-four".

Divisors: 1 2 56570175187 113140350374