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1131404211411 = 3377134737137
BaseRepresentation
bin10000011101101100111…
…100100011010011010011
311000011100111122000000220
4100131230330203103103
5122014103434231121
62223432050444123
7144512152056135
oct20355474432323
94004314560026
101131404211411
113a690a1aa921
12163334b93643
13828ca0649a6
143ca901dd055
151e66ca026c6
hex1076cf234d3

1131404211411 has 4 divisors (see below), whose sum is σ = 1508538948552. Its totient is φ = 754269474272.

The previous prime is 1131404211401. The next prime is 1131404211439. The reversal of 1131404211411 is 1141124041311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131404211411 - 213 = 1131404203219 is a prime.

It is a super-2 number, since 2×11314042114112 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1131404211401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188567368566 + ... + 188567368571.

It is an arithmetic number, because the mean of its divisors is an integer number (377134737138).

Almost surely, 21131404211411 is an apocalyptic number.

1131404211411 is a deficient number, since it is larger than the sum of its proper divisors (377134737141).

1131404211411 is an equidigital number, since it uses as much as digits as its factorization.

1131404211411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 377134737140.

The product of its (nonzero) digits is 384, while the sum is 24.

Adding to 1131404211411 its reverse (1141124041311), we get a palindrome (2272528252722).

The spelling of 1131404211411 in words is "one trillion, one hundred thirty-one billion, four hundred four million, two hundred eleven thousand, four hundred eleven".

Divisors: 1 3 377134737137 1131404211411