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11314044003 = 310735246243
BaseRepresentation
bin10101000100101111…
…01001110001100011
31002012111100222121210
422202113221301203
5141132343402003
65110403121203
7550241534013
oct124227516143
932174328553
1011314044003
114886534799
122239073203
1310b40018c2
1479489bc43
15463424503
hex2a25e9c63

11314044003 has 8 divisors (see below), whose sum is σ = 15226377408. Its totient is φ = 7472203304.

The previous prime is 11314043977. The next prime is 11314044067. The reversal of 11314044003 is 30044041311.

11314044003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11314044003 - 210 = 11314042979 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11314048003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17622801 + ... + 17623442.

It is an arithmetic number, because the mean of its divisors is an integer number (1903297176).

Almost surely, 211314044003 is an apocalyptic number.

11314044003 is a deficient number, since it is larger than the sum of its proper divisors (3912333405).

11314044003 is a wasteful number, since it uses less digits than its factorization.

11314044003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35246353.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 11314044003 its reverse (30044041311), we get a palindrome (41358085314).

The spelling of 11314044003 in words is "eleven billion, three hundred fourteen million, forty-four thousand, three".

Divisors: 1 3 107 321 35246243 105738729 3771348001 11314044003