11314053131 has 8 divisors (see below), whose sum is σ = 11591695584. Its totient is φ = 11039696640.

The previous prime is 11314053083. The next prime is 11314053151. The reversal of 11314053131 is 13135041311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11314053131 is a prime.

It is a super-2 number, since 2×11314053131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11314053097 and 11314053106.

It is not an unprimeable number, because it can be changed into a prime (11314053151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 814520 + ... + 828293.

It is an arithmetic number, because the mean of its divisors is an integer number (1448961948).

Almost surely, 2^11314053131 is an apocalyptic number.

11314053131 is a deficient number, since it is larger than the sum of its proper divisors (277642453).

11314053131 is an equidigital number, since it uses as much as digits as its factorization.

11314053131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1642981.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 11314053131 its reverse (13135041311), we get a palindrome (24449094442).

The spelling of 11314053131 in words is "eleven billion, three hundred fourteen million, fifty-three thousand, one hundred thirty-one".