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11314103 = 39728499
BaseRepresentation
bin101011001010…
…001110110111
3210021211000212
4223022032313
510344022403
61042300035
7165111503
oct53121667
923254025
1011314103
1164284a9
12395761b
132461a48
141707303
15ed74d8
hexaca3b7

11314103 has 4 divisors (see below), whose sum is σ = 11343000. Its totient is φ = 11285208.

The previous prime is 11314099. The next prime is 11314109. The reversal of 11314103 is 30141311.

11314103 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30141311 = 31795083.

It is a cyclic number.

It is not a de Polignac number, because 11314103 - 22 = 11314099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11314109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13853 + ... + 14646.

It is an arithmetic number, because the mean of its divisors is an integer number (2835750).

Almost surely, 211314103 is an apocalyptic number.

11314103 is a deficient number, since it is larger than the sum of its proper divisors (28897).

11314103 is an equidigital number, since it uses as much as digits as its factorization.

11314103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28896.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 11314103 is about 3363.6443034304. The cubic root of 11314103 is about 224.4950189287.

Adding to 11314103 its reverse (30141311), we get a palindrome (41455414).

The spelling of 11314103 in words is "eleven million, three hundred fourteen thousand, one hundred three".

Divisors: 1 397 28499 11314103