11314113233 has 2 divisors, whose sum is σ = 11314113234. Its totient is φ = 11314113232.

The previous prime is 11314113203. The next prime is 11314113247. The reversal of 11314113233 is 33231141311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8978131009 + 2335982224 = 94753^2 + 48332^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314113233 - 2¹² = 11314109137 is a prime.

It is a super-3 number, since 3×11314113233³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11314113199 and 11314113208.

It is not a weakly prime, because it can be changed into another prime (11314113203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657056616 + 5657056617.

It is an arithmetic number, because the mean of its divisors is an integer number (5657056617).

Almost surely, 2^11314113233 is an apocalyptic number.

It is an amenable number.

11314113233 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314113233 is an equidigital number, since it uses as much as digits as its factorization.

11314113233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 648, while the sum is 23.

Adding to 11314113233 its reverse (33231141311), we get a palindrome (44545254544).

The spelling of 11314113233 in words is "eleven billion, three hundred fourteen million, one hundred thirteen thousand, two hundred thirty-three".