Base | Representation |
---|---|
bin | 10101000100101111… |
… | …11111100001110111 |
3 | 1002012111112111212002 |
4 | 22202113333201313 |
5 | 141132404224421 |
6 | 5110405045515 |
7 | 550242354551 |
oct | 124227774167 |
9 | 32174474762 |
10 | 11314133111 |
11 | 4886595736 |
12 | 22390b689b |
13 | 10b4033328 |
14 | 7948c24d1 |
15 | 463440b0b |
hex | 2a25ff877 |
11314133111 has 2 divisors, whose sum is σ = 11314133112. Its totient is φ = 11314133110.
The previous prime is 11314133087. The next prime is 11314133119. The reversal of 11314133111 is 11133141311.
It is a strong prime.
It is an emirp because it is prime and its reverse (11133141311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11314133111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11314133119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657066555 + 5657066556.
It is an arithmetic number, because the mean of its divisors is an integer number (5657066556).
Almost surely, 211314133111 is an apocalyptic number.
11314133111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314133111 is an equidigital number, since it uses as much as digits as its factorization.
11314133111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 108, while the sum is 20.
Adding to 11314133111 its reverse (11133141311), we get a palindrome (22447274422).
The spelling of 11314133111 in words is "eleven billion, three hundred fourteen million, one hundred thirty-three thousand, one hundred eleven".
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