Base | Representation |
---|---|
bin | 1010010010100100011110… |
… | …0010101101111111111101 |
3 | 1111001121210011021112100001 |
4 | 2210221013202231333331 |
5 | 2440332331400010214 |
6 | 40021351314434301 |
7 | 2245264016263402 |
oct | 244510742557775 |
9 | 44047704245301 |
10 | 11314144141309 |
11 | 3672335454999 |
12 | 132890bb92991 |
13 | 640bc468bb39 |
14 | 2b1870d922a9 |
15 | 14949096ec74 |
hex | a4a478adffd |
11314144141309 has 2 divisors, whose sum is σ = 11314144141310. Its totient is φ = 11314144141308.
The previous prime is 11314144141303. The next prime is 11314144141327. The reversal of 11314144141309 is 90314144141311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8208671946084 + 3105472195225 = 2865078^2 + 1762235^2 .
It is a cyclic number.
It is not a de Polignac number, because 11314144141309 - 23 = 11314144141301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11314144141301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657072070654 + 5657072070655.
It is an arithmetic number, because the mean of its divisors is an integer number (5657072070655).
Almost surely, 211314144141309 is an apocalyptic number.
It is an amenable number.
11314144141309 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314144141309 is an equidigital number, since it uses as much as digits as its factorization.
11314144141309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 37.
The spelling of 11314144141309 in words is "eleven trillion, three hundred fourteen billion, one hundred forty-four million, one hundred forty-one thousand, three hundred nine".
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