Base | Representation |
---|---|
bin | 10101000100110000… |
… | …10000111100011001 |
3 | 1002012111200010200221 |
4 | 22202120100330121 |
5 | 141132414020231 |
6 | 5110410400041 |
7 | 550243102531 |
oct | 124230207431 |
9 | 32174603627 |
10 | 11314204441 |
11 | 4886634291 |
12 | 2239130021 |
13 | 10b4059937 |
14 | 7949004c1 |
15 | 463456d11 |
hex | 2a2610f19 |
11314204441 has 4 divisors (see below), whose sum is σ = 11483073232. Its totient is φ = 11145335652.
The previous prime is 11314204381. The next prime is 11314204537. The reversal of 11314204441 is 14440241311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14440241311 = 3769 ⋅3831319.
It is a cyclic number.
It is not a de Polignac number, because 11314204441 - 231 = 9166720793 is a prime.
It is a super-2 number, since 2×113142044412 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11315204441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84434295 + ... + 84434428.
It is an arithmetic number, because the mean of its divisors is an integer number (2870768308).
Almost surely, 211314204441 is an apocalyptic number.
It is an amenable number.
11314204441 is a deficient number, since it is larger than the sum of its proper divisors (168868791).
11314204441 is an equidigital number, since it uses as much as digits as its factorization.
11314204441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 168868790.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 11314204441 its reverse (14440241311), we get a palindrome (25754445752).
The spelling of 11314204441 in words is "eleven billion, three hundred fourteen million, two hundred four thousand, four hundred forty-one".
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