14440241311 has 4 divisors (see below), whose sum is σ = 14444076400. Its totient is φ = 14436406224.

The previous prime is 14440241297. The next prime is 14440241323. The reversal of 14440241311 is 11314204441.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11314204441 = 67 ⋅168868723.

It is a cyclic number.

It is not a de Polignac number, because 14440241311 - 2¹⁵ = 14440208543 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14440241111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1911891 + ... + 1919428.

It is an arithmetic number, because the mean of its divisors is an integer number (3611019100).

Almost surely, 2^14440241311 is an apocalyptic number.

14440241311 is a deficient number, since it is larger than the sum of its proper divisors (3835089).

14440241311 is an equidigital number, since it uses as much as digits as its factorization.

14440241311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3835088.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 14440241311 its reverse (11314204441), we get a palindrome (25754445752).

The spelling of 14440241311 in words is "fourteen billion, four hundred forty million, two hundred forty-one thousand, three hundred eleven".